#include <stdio.h>
#include <iostream>
#define N 5
using namespace std;
int solve(int a[],int n)
{
int count=0;
for(int i=0;i<n-1;i++)
{
for(int j=i+1;j<n;j++){
if(a[i]>a[j])
count++;}
}
return count;
}
int main()
{
int arr[5]={6,2,4,3,5};
int s;
s=sizeof(arr)/sizeof(int);
printf("此序列中存在的逆序数为:%d\n",solve(arr,s));
system("pause");
return 0;
}