编辑代码

//1.20 关系表达式

#include<stdio.h>
int main(){

  char c='k';

  int i=1,j=2,k=3;

  float x=3e+5,y=0.85;
  printf("%f\n",x);
  printf("%d,%d\n",'a'+5<c,-i-2*j>=k+1);

  printf("%d,%d\n",1<j<5,x-5.25<=x+y);

  printf("%d,%d\n",i+j+k==-2*j,k==j==i+5);
  return 0;
 }