#有四个数字:1,2,3,4,能组成多少个互不相同且无重复数字的三位数?各是多少? count=0 for i in range(1,5): for j in range(1,5): for k in range(1,5): if i!=j and j!=k and k!=i: a=100*i+10*j+k count=count+1 print(a) print("一共有%d个。"%count)