function solution(arr1, arr2){
let diff1 = [] // 只有arr1有
let diff2 = [] // 只有arr2有
for(let t of arr1){
if(!arr2.includes(t)){
diff1.push(t)
}
}
for(let t of arr2){
if(!arr1.includes(t)){
diff2.push(t)
}
}
//
if(diff1.length===0 && diff2.length ===0){
console.log("same")
}
if(diff1.length===0 && diff2.length !==0){
console.log("arr1 in arr2")
}
if(diff1.length!==0 && diff2.length ===0){
console.log("arr2 in arr1")
}
if(diff1.length!==0 && diff2.length !==0){
console.log("arr2 different from arr1")
}
}
solution([1,2,3], [2,3])
const a = [1,2]
const b = a
solution([1,2,3,a], [2,3,b])
console