int max(int a, int b) {
return (a > b) ? a : b;
}
int maxCoins(int board[][6], int n, int m) {
int dp[n][m];
// 初始化第一个元素
dp[0][0] = board[0][0];
// 初始化第一行和第一列
for (int i = 1; i < n; i++)
dp[i][0] = dp[i-1][0] + board[i][0];
for (int j = 1; j < m; j++)
dp[0][j] = dp[0][j-1] + board[0][j];
// 动态规划递推
for (int i = 1; i < n; i++) {
for (int j = 1; j < m; j++) {
dp[i][j] = board[i][j] + max(dp[i-1][j], dp[i][j-1]);
}
}
// 返回右下角位置的最大硬币数
return dp[n-1][m-1];
}
int main() {
int board[3][3] = {
{0, 0, 0,0,1,0},
{0, 1, 0,1,0,0},
{0, 0, 0,1,0,1},
{0, 0, 1,0,0,1},
{1, 0, 0,0,1,0},
};
int n = 5;
int m = 6;
int result = maxCoins(board, n, m);
printf("最大硬币数: %d\n", result);
return 0;
}