编辑代码

#include <stdio.h>
int main () 
{
    int i;
    double bonus,bon1,bon2,bon4,bon6,bon10;
    int branch;
    bon1=100000*0.1;
    bon2=bon1+100000*0.075;
    bon4=b0n2+200000*0.05;
    b0n6=bon4+200000*0.03;
    bon10=bon6+400000*0.015;
    printf("请输入利润i:");
    scanf("%d",&i);
    branch=i/100000;
    if(branch>10)   branch=10;
    switch(branch)
    {  case 0:bonus=i*0.1;break;
       case 1:bonus=bon1+(i-100000)*0.075;break;
       case 3:bonus=bon2+(i-200000)*0.05;break;
       case 4:
       case 5:bonus=bon4+(i-400000)*0.03;break;
       case 6:
       case 7:
       case 8：
       case 9:bonus=bon6+(i-600000)*0.015；break;
       case 10：bonus=bon10+(i-1000000)*0.01;
    }
    printf("奖金是%10.2f\n",bonus);
      return 0;
}