const arr =[2,4,1,6]
const res = arr.reduce((accumulator, currentValer) => accumulator+currentValer,0)
console.log(res)
function sum (a,b) {
return a+b
}
const r = sum(2,3)
console.log(r)
const p1 = 2;
const p2 = 3
Promise.all([p1,p2]).then(res=>{
console.log(res)
})