//set let a = new Set([1, 2, 3, 4, 5]); let b = new Set([4, 3, 2]); // 交集 let sum = new Set([...a].filter(x => b.has(x))); // console.log(Array.from(sum)) //差集 let difference = new Set([...a].filter( x => !b.has(x))) // console.log(Array.from(difference)) //陷阱 let arr = [{},{},2, ,3,2,3,null,'null',NaN,NaN,[2,3,],[2,3]] let newarr = [] for(let item of arr){ }