SOURCE

let a = ['a','b','c','d']
let b = ['t','e']

let s = b.map(el => a.includes(el)).some(item => item)
for(let i = 0 ; i < b.length; i++){
    if(a.includes(b[i])){
        
    }
}
console.log(s)
console 命令行工具 X clear

                    
>
console