let arr = [
{ name: '张三' },
{ name: '张三' },
{ name: '李四' },
];
// 方式一
let map1 = new Map();
let res1 = arr.reduce((pre, cur) => {
if (!map1.has(cur.name)) {
map1.set(cur.name, true)
pre.push(cur)
}
return pre;
}, [])
console.log(res1)
// 方式二
let map2 = new Map();
let res2 = arr.filter((item) => {
if (!map2.has(item.name)) {
map2.set(item.name, true)
return item;
}
})
// 简化方式二
let map3 = new Map();
let res3 = arr.filter((item) => !map3.has(item.name) && map3.set(item.name, true))
console.log(res3)
console