let res = [];
let mc = '2012-05-01'
let sc = '2020-08-01'
let b1 = ['2015-01-28', '2017-12-31']
let c2 = ['2018-01-07', '2020-09-01']
let d3 = ['2011-01-07', '2012-05-01']
let e4 = ['2012-05-01', '2015-02-21']
let mstr = [b1, c2, d3, e4];
for (let i = 0; i < mstr.length; i++) {
if(mstr[i][1] > sc){
console.log('任职结束日期不能晚于入职日期');
}else{
console.log(mstr[i]);
if (mstr[i][0] >= mc && mstr[i][1] > mc) {
res.push(mstr[i])
} else if (mstr[i][0] < mc && mstr[i][1] > mc) {
res.push([mc, mstr[i][1]])
}
}
}
console.log('-----------------------')
res.sort();
for (let i = 0; i < res.length; i++) {
console.log(res[i])
}
console.log('-----------------------')
let gzrq = res[0][0]
for (let i = 0; i < res.length; i++) {
let first = Date.parse(res[i][1])
let seccend = ''
if (i == res.length - 1) {
seccend = Date.parse(sc)
} else {
seccend = Date.parse(res[i+1][0])
}
let diffDay = (seccend - first) / (1*24*60*60*1000)
console.log('上一段与下一段工作相差天数:'+diffDay)
if(diffDay > 180){
console.log('断档了半年')
break
}
}
console.log('参加工作日期:'+gzrq)
console