var nums = [-1,2,1,-4],target = 1
$(function(){
console.log(lengthOfLongestSubstring('abcbc'))
})
let lengthOfLongestSubstring = function (str) {
let n = str.length
// 滑动窗口为s[left...right]
let left = 0
let right = -1
let freqMap = {} // 记录当前子串中下标对应的出现频率
let max = 0 // 找到的满足条件子串的最长长度
while (left < n) {
let nextLetter = str[right + 1]
if (!freqMap[nextLetter] && nextLetter !== undefined) {
freqMap[nextLetter] = 1
right++
} else {
freqMap[str[left]] = 0
left++
}
max = Math.max(max, right - left + 1)
}
return max
}
console