编辑代码

#include <stdio.h>

int main () {

    int a = 1, b = 2, c = 3, d = 4, e = 5;
    int *p[5] = {&a, &b, &c, &d, &e};
    int i = 0;

    for(i = 0; i < 5; i++)
    {
        printf("第%d个元素的地址是%d。\n",i+1 ,p[i]);
    }

	return 0;
}