let arr=[11,8,6,22,3,9,0,1,44] let target=23 const fn=(result,target) => { for(let i=0;i<result.length;i++) { for(let j=i+1;j<result.length;j++) { if(result[i]+result[j]===target) { return result[i]+"和"+result[j] } } } return null } console.log(fn(arr,target)) function twoSumHash(nums, target) { const map = new Map(); // 值 -> 索引 for (let i = 0; i < nums.length; i++) { const need = target - nums[i]; if (map.has(need)) { return [need, nums[i]] } map.set(nums[i], i); } return null; }