import java.util.Arrays;
publicclassSolution {
publicstaticvoidmain(String[] args) {
int[] x = {10, 20, 30, 40, 50, 60, 70, 80, 90};
int k = 3;
int index = findClosestSubsequenceIndex(x, k);
System.out.println("The index is: " + index);
}
publicstaticintfindClosestSubsequenceIndex(int[] x, int k) {
// Step 1: Calculate the median of the array.int[] sortedX = Arrays.copyOf(x, x.length);
Arrays.sort(sortedX);
int median;
int n = x.length;
if (n % 2 == 0) {
// For an even number of elements, take the lower middle value.
median = sortedX[n / 2 - 1];
} else {
// For an odd number of elements, take the middle value.
median = sortedX[n / 2];
}
int bestIndex = -1;
int minDiff = Integer.MAX_VALUE;
// Step 2 and 3: Iterate over all possible subsequences of length k.for (int i = 0; i <= x.length - k; i++) {
int alternatingSum = 0;
boolean add = true;
for (int j = i; j < i + k; j++) {
alternatingSum += add ? x[j] : -x[j];
add = !add; // Alternate between adding and subtracting
}
// Calculate the absolute difference from the median.int diff = Math.abs(alternatingSum - median);
// Update index if this subsequence is closer to the median or equal but larger index.if (diff < minDiff || (diff == minDiff && i > bestIndex)) {
minDiff = diff;
bestIndex = i;
}
}
return bestIndex;
}
}