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const arr =[2,4,1,6]

const res = arr.reduce((accumulator, currentValer) => accumulator+currentValer,0)

console.log(res)

function sum (a,b) {
    return a+b
}

const r = sum(2,3)

console.log(r)


const p1 = 2;
const p2 = 3

Promise.all([p1,p2]).then(res=>{
    console.log(res)
})
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