编辑代码

num1=io.read("*n")
num2=io.read("*n")

--约数和函数
function Friendly (a)
    sum=0
    for i=1,a-1,1 do
       if a%i==0 then
       sum=sum+i
       end
    end
    return sum
end

sum1=Friendly(num1)
sum2=Friendly(num2)

if sum1==num2 and sum2==num1 then
    print("yes")
else
    print("no")
end